halcon算子

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halcon算子

2024-07-02 18:08| 来源: 网络整理| 查看: 265

*求交叉区域intersection (Region1, Region2, RegionIntersection)

*求circle与轮廓的交叉点 intersection_circle_contour_xld (Contour, CircleRow, CircleColumn, CircleRadius, 0, 6.28318, 'positive', Row, Column)

*求直线与轮廓的交叉点(计算的时候会自动延长直线,得到直线的延长线与轮廓的交叉点) intersection_line_contour_xld (Contour, LineRow1, LineColumn1, LineRow2, LineColumn2, Row, Column, IsOverlapping)

如上图,想要计算红色直线与矩形轮廓的交叉点,得到了A、B两个点

*求两个圆的交叉点 intersection_circles (Row, Column, Row, 0, 6.28318, 'positive', Row, Column, Row, 0, 6.28318, 'positive', Row1, Column1, IsOverlapping)

*求直线和圆的交叉点 intersection_line_circle (LineRow1, LineColumn1, LineRow2, LineColumn2, CircleRow1, CircleColumn1, Radius, 0, 6.28318, 'positive', Row, Column)

*求两条直线的交叉点 intersection_lines (Line1Row1, Line1Column1, Line1Row2, Line1Column2, Line2Row1, Line2Column1, Line2Row2, Line2Column2, Row, Column, IsOverlapping1)

*求分割片段与直线的交叉区域 intersection_segment_line



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