|
已知点A（x1，y1）、B（x2，y2）为直线L1上两个点，点C（x3，y3）、D（x4，y4）为直线L2上两个点，求解两个直线的方程以及交点坐标，直接贴代码
#include
using namespace std;
//定义Point2f结构体
struct Point2f
{
float x;
float y;
};
// 定义直线参数结构体
struct LinePara
{
float k;
float b;
};
// 获取直线参数
void getLinePara(float& x1, float& y1, float& x2, float& y2, LinePara & LP)
{
double m = 0;
// 计算分子
m = x2 - x1;
if (0 == m)
{
LP.k = 10000.0;
LP.b = y1 - LP.k * x1;
}
else
{
LP.k = (y2 - y1) / (x2 - x1);
LP.b = y1 - LP.k * x1;
}
}
// 获取交点
bool getCross(float & x1, float &y1, float & x2, float & y2, float & x3, float &y3, float & x4, float & y4, Point2f & pt){
LinePara para1, para2;
getLinePara(x1, y1, x2, y2, para1);
getLinePara(x3, y3, x4, y4, para2);
// 判断是否平行
if (abs(para1.k - para2.k) > 0.5)
{
pt.x = (para2.b - para1.b) / (para1.k - para2.k);
pt.y = para1.k * pt.x + para1.b;
return true;
}
else
{
return false;
}
}
void main()
{
Point2f pt1, pt2, pt3, pt4, pt;
pt1.x = 1.0;
pt1.y = 1.0;
pt2.x = 2.0;
pt2.y = 2.0;
pt3.x = 0.0;
pt3.y = 2.0;
pt4.x = 2.0;
pt4.y = 0.0;
getCross(pt1.x, pt1.y, pt2.x, pt2.y, pt3.x, pt3.y, pt4.x, pt4.y, pt);
cout |