数据库设计(表与表之间的3种关系)

您所在的位置:网站首页 依赖关系有哪几种数学模型 数据库设计(表与表之间的3种关系)

数据库设计(表与表之间的3种关系)

2024-07-12 18:48| 来源: 网络整理| 查看: 265

表与表之间一般存在三种关系,即一对一,一对多,多对多关系。 下面分别就三种关系讲解数据库相关设计的思路和思考过程;

(1)一对一关系 例如,下面的一张表,保存了人的相关信息,有男有女,要求查处所有的夫妻。 sql代码:

CREATE TABLE IF NOT EXISTS person( id INT PRIMARY KEY AUTO_INCREMENT, sname VARCHAR(10), sex CHAR(1), husband INT, wife INT ); INSERT INTO person VALUES(1,'小花','0',3,0); INSERT INTO person VALUES(2,'小明','1',0,4); INSERT INTO person VALUES(3,'张三','1',0,1); INSERT INTO person VALUES(4,'小丽','0',2,0); INSERT INTO person VALUES(5,'王五','1',0,0);

sql代码对应的person表: 这里写图片描述 从表中可以看出,小花和张三是夫妻,小明和小丽是夫妻。通常为了查询方便,需要两个表,但实际项目中为了省空间,通常只建一个表,要实现一对一查询,可以建立两个视图(虚表) * 有个小细节提一下,视图只是个逻辑概念,并不独立占用物理内存,它依附于数据表,对视图进行修改时相应的表数据也会盖改动*

CREATE VIEW men AS (SELECT * FROM person WHERE sex='1'); CREATE VIEW women AS (SELECT * FROM person WHERE sex='0');

men视图: 这里写图片描述 women视图: 这里写图片描述

执行查询: 方式一(原始方法):SELECT men.sname AS husband,women.sname AS wife FROM men,women WHERE men.id = women.husband AND women.id = men.wife;

方式二(连接方法):SELECT men.sname AS husband,women.sname AS wife FROM men INNER JOIN women ON men.id = women.husband AND women.id = men.wife;

二、一对多关系 例如:一个人可以拥有多辆汽车,要求查询某个人拥有的所有车辆。 分析:这种情况其实也可以采用 一张表,但因为一个人可以拥有多辆汽车,如果采用一张表,会造成冗余信息过多。好的设计方式是,人和车辆分别单独建表,那么如何将两个表关联呢?有个巧妙的方法,在车辆的表中加个外键字段(人的编号)即可。 * (思路小结:’建两个表,一’方不动,’多’方添加一个外键字段)*

sql代码:

//建立人员表 CREATE TABLE human( id VARCHAR(12) PRIMARY KEY, sname VARCHAR(12), age INT, sex CHAR(1) ); INSERT INTO human VALUES('H001','小王',27,'1'); INSERT INTO human VALUES('H002','小明',24,'1'); INSERT INTO human VALUES('H003','张慧',28,'0'); INSERT INTO human VALUES('H004','李小燕',35,'0'); INSERT INTO human VALUES('H005','王大拿',29,'1'); INSERT INTO human VALUES('H006','周强',36,'1'); //建立车辆信息表 CREATE TABLE car( id VARCHAR(12) PRIMARY KEY, mark VARCHAR(24), price NUMERIC(6,2), hid VARCHAR(12), CONSTRAINT fk_human FOREIGN KEY(hid) REFERENCES human(id) ); INSERT INTO car VALUES('C001','BMW',65.99,'H001'); INSERT INTO car VALUES('C002','BenZ',75.99,'H002'); INSERT INTO car VALUES('C003','Skoda',23.99,'H001'); INSERT INTO car VALUES('C004','Peugeot',20.99,'H003'); INSERT INTO car VALUES('C005','Porsche',295.99,'H004'); INSERT INTO car VALUES('C006','Honda',24.99,'H005'); INSERT INTO car VALUES('C007','Toyota',27.99,'H006'); INSERT INTO car VALUES('C008','Kia',18.99,'H002'); INSERT INTO car VALUES('C009','Bentley',309.99,'H005');

sql代码对应的人员表: 这里写图片描述 sql代码对应的车辆信息表: 这里写图片描述 执行查询:SELECT human.sname AS 车主,car.mark AS 车辆 FROM human,car WHERE human.id = car.hid;

`SELECT human.sname AS 车主,car.mark AS 车辆 FROM human INNER JOIN car WHERE human.id = car.hid;

三、多对多关系` 例如:学生选课,一个学生可以选修多门课程,每门课程可供多个学生选择。 分析:这种方式可以按照类似一对多方式建表,但冗余信息太多,好的方式是实体和关系分离并单独建表,实体表为学生表和课程表,关系表为选修表,其中关系表采用联合主键的方式(由学生表主键和课程表主键组成)建表。

sql代码:

//建立学生表 CREATE TABLE student( id VARCHAR(10) PRIMARY KEY, sname VARCHAR(12), age INT, sex CHAR(1), class VARCHAR(6) ); INSERT INTO student VALUES('p0001','王军',20,1,'c101'); INSERT INTO student VALUES('p0002','张宇',21,1,'c101'); INSERT INTO student VALUES('p0003','刘飞',22,1,'c102'); INSERT INTO student VALUES('p0004','赵燕',18,0,'c103'); INSERT INTO student VALUES('p0005','曾婷',19,0,'c103'); INSERT INTO student VALUES('p0006','周慧',21,0,'c104'); INSERT INTO student VALUES('p0007','小红',23,0,'c104'); INSERT INTO student VALUES('p0008','杨晓',18,0,'c104'); INSERT INTO student VALUES('p0009','李杰',20,1,'c105'); INSERT INTO student VALUES('p0010','张良',22,1,'c105'); //建立课程表 CREATE TABLE course( id VARCHAR(10) PRIMARY KEY, sname VARCHAR(12), credit NUMERIC(2,1), teacher VARCHAR(12) ); INSERT INTO course VALUES('C001','Java',3.5,'李老师'); INSERT INTO course VALUES('C002','高等数学',5.0,'赵老师'); INSERT INTO course VALUES('C003','JavaScript',3.5,'王老师'); INSERT INTO course VALUES('C004','离散数学',3.5,'卜老师'); INSERT INTO course VALUES('C005','数据库',3.5,'廖老师'); INSERT INTO course VALUES('C006','操作系统',3.5,'张老师'); //建立选修表 CREATE TABLE sc( sid VARCHAR(10), cid VARCHAR(10) ); ALTER TABLE sc ADD CONSTRAINT pk_sc PRIMARY KEY(sid,cid); ALTER TABLE sc ADD CONSTRAINT fk_student FOREIGN KEY(sid) REFERENCES student(id); ALTER TABLE sc ADD CONSTRAINT fk_course FOREIGN KEY(cid) REFERENCES course(id); INSERT INTO sc VALUES('S0001','C001'); INSERT INTO sc VALUES('S0001','C002'); INSERT INTO sc VALUES('S0001','C003'); INSERT INTO sc VALUES('S0002','C001'); INSERT INTO sc VALUES('S0002','C004'); INSERT INTO sc VALUES('S0003','C002'); INSERT INTO sc VALUES('S0003','C005'); INSERT INTO sc VALUES('S0004','C003'); INSERT INTO sc VALUES('S0005','C001'); INSERT INTO sc VALUES('S0006','C004'); INSERT INTO sc VALUES('S0007','C002'); INSERT INTO sc VALUES('S0008','C003'); INSERT INTO sc VALUES('S0009','C001'); INSERT INTO sc VALUES('S0009','C005');

sql代码对应的学生表: 这里写图片描述 sql代码对应的课程表: 这里写图片描述 sql代码对应的选课表: 这里写图片描述 执行查询:(没有选课的学生信息和无学生选的课程信息) 普通方式:

SELECT * FROM student WHERE student.id NOT IN (SELECT sid FROM sc); SELECT * FROM course WHERE course.id NOT IN (SELECT cid FROM sc);

关联方式:

SELECT student.* FROM student LEFT JOIN sc ON student.id=sc.sid LEFT JOIN course ON course.id = sc.cid WHERE course.sname IS NULL; SELECT course.* FROM course LEFT JOIN sc ON course.id=sc.cid LEFT JOIN student ON student.id = sc.sid WHERE student.sname IS NULL;


【本文地址】


今日新闻


推荐新闻


CopyRight 2018-2019 办公设备维修网 版权所有 豫ICP备15022753号-3