java 模拟HTTP2.0请求 |
您所在的位置：网站首页 › java模拟http › java 模拟HTTP2.0请求 |
java 模拟HTTP2.0请求
|
关于HTTP/1.0 HTTP/1.1 HTTP/2.0 https://www.cnblogs.com/heluan/p/8620312.html 目前主流网站如某宝某东都已经支持，下面将用java程序模拟发起HTTP/2.0 GET请求。 要求： Jdk 1.9+编译： jdk1.9工具：idea第一步 创建项目
第二步 source目录下创建module-info.java module demo1 { requires jdk.incubator.httpclient; }第三步 写代码 package com.example.demo1; import jdk.incubator.http.HttpClient; import jdk.incubator.http.HttpRequest; import jdk.incubator.http.HttpResponse; import java.io.IOException; import java.net.URI; public class HttpClientUsg { public String requestByGetMethod(String url) throws IOException, InterruptedException { HttpClient httpClient = HttpClient.newBuilder().build(); HttpRequest request = HttpRequest.newBuilder(URI.create(url)) // .header("Content-Type", "application/json") .version(HttpClient.Version.HTTP_2) .GET() .build(); HttpResponse httpResponse = httpClient.send(request, HttpResponse.BodyHandler.asString()); System.out.println(httpResponse.toString()); System.out.println(httpResponse.headers().toString()); System.out.println(httpResponse.body().toString()); return url; } public static void main(String args[]) { HttpClientUsg httpClientUtil = new HttpClientUsg(); String url = "https://www.baidu.com"; String res = null; try { res = httpClientUtil.requestByGetMethod(url).split("/n")[0]; System.out.println(res); } catch (Exception e) { e.printStackTrace(); } } }
|
【本文地址】