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学以致用

2024-07-10 19:58| 来源: 网络整理| 查看: 265

看到教材中的一个示例,可从身份证号提取性别、出生年月日、年龄。但是有个问题,即,当仅选择一个单元格时,会报错(类型错误)。于是,修改了这个问题。

现在,仅选择一行,也可以进行提取。

代码:

Sub extractIDInfo() '利用VBA从身份证号码中提取性别、出生日期和年龄 Dim rng As Range, i As Integer, Mystr As String, arr(), arr2() If TypeName(Selection) "Range" Then MsgBox "请选择存放身份证号码的区域": Exit Sub Set rng = Intersect(Selection, ActiveSheet.UsedRange) If rng.Columns.Count > 1 Then MsgBox "只能选择单列", vbOKOnly + vbInformation, "出错提示": Exit Sub If rng(1) = "" Then MsgBox "请选择身份证号码存放区域", vbOKOnly + vbInformation, "出错提示": Exit Sub ReDim arr(1 To rng.Rows().Count, 1 To 1) For i = 1 To rng.Rows().Count arr(i, 1) = rng(i).Value Next ReDim arr2(1 To UBound(arr), 1 To 3) For i = 1 To UBound(arr) If Len(arr(i, 1)) = 15 Or Len(arr(i, 1)) = 18 Then arr2(i, 1) = IIf((Mid(arr(i, 1), 15, 3) Mod 2), "男", "女") If Len(arr(i, 1)) = 15 And Mid(arr(i, 1), 7, 1) = 0 Then Mystr = "20" & Mid(arr(i, 1), 7, 2) & "-" & Mid(arr(i, 1), 9, 2) & "-" & Mid(arr(i, 1), 11, 2) If Len(arr(i, 1)) = 15 And Mid(arr(i, 1), 7, 1) > 0 Then Mystr = "19" & Mid(arr(i, 1), 7, 2) & "-" & Mid(arr(i, 1), 9, 2) & "-" & Mid(arr(i, 1), 11, 2) If Len(arr(i, 1)) = 18 Then Mystr = Mid(arr(i, 1), 7, 4) & "-" & Mid(arr(i, 1), 11, 2) & "-" & Mid(arr(i, 1), 13, 2) arr2(i, 2) = Mystr arr2(i, 3) = Evaluate("DATEDIF(" & DateSerial(Split(Mystr, "-")(0), Split(Mystr, "-")(1), Split(Mystr, "-")(2)) * 1 & ", NOW()," & """Y""" & ")") End If Next i rng.Offset(0, 1).Resize(UBound(arr), 3) = arr2 End Sub


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