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sửa: `(x-\frac{2}{3}).(-\frac{4}{9})+\frac{5}{7}=1\frac{5}{7}` `=> (x-\frac{2}{3}).(-\frac{4}{9})=\frac{12}{7}-\frac{5}{7}` `=> (x-\frac{2}{3}).(-\frac{4}{9})=1` `=> x-\frac{2}{3}=1.(-\frac{9}{4})` `=> x-\frac{2}{3}=-\frac{9}{4}` `=> x=\frac{-9}{4}+\frac{2}{3}` `=> x=\frac{-27}{12}+\frac{8}{12}` `=> x=-\frac{19}{12}` Vậy `x=-\frac{19}{12}` Rút gọnsửa: `(x-\frac{2}{3}).(-\frac{4}{9})+\frac{5}{7}=1\frac{5}{7}` `=> (x-\frac{2}{3}).(-\frac{4}{9})=\frac{12}{7}-\frac{5}{7}` `=> (x-\frac{2}{3}).(-\frac{4}{9})=1` `=> x-\frac{2}{3}=1.(-\frac{9}{4})` `=> x-\frac{2}{3}=-\frac{9}{4}` `=> x=\frac{-9}{4}+\fr... xem thêm