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1、第二章选频网络 注意：有部分答案有差异； 3-1题是2-1题； 只有计算题答案和部分问答题； 答案不齐全。 ( pF).(LC H)(.QR L R f fQ ( k Hz )f MHz : f . . 15910159101432 11 159101432 10100 10 1001010 1012 10109901012 113 62620 60 3 6 70 0 3670 0 = = = = = = = , .CL CL) ( , .CL CL) ( , .CL CL) : ( 22 0 2 11 0 1 22 0 2 11 0 1 22 0 2 11 0 1 113 112 11123

2、 = = = RR C LR )LCL(j R )LCLR(j CLR Cj RLj R )Cj L) ( Rj ( R : Z =+=+ + =+ + = 2112 11 1 1 33 2 200 200 2 0 0 0 0 ) ( ) ( )( ) ( ) ( ) ) ( ) ( ) ( ) ( ) )3 1801040450105351432 112 1535100160512 40535450160515143 1 22320 22 22 H.CCL pF- CCC pF CCC : =+=+= =+=+ =+=+ 。 L C C ( ) ( ) ( ) ( )mVVQVV mA.RV

3、I HCL RC : Q -S mCo mLo m -o m o m - - 212101212 205101 1121010010511432 11 21251010010511432 1153 30 3 1 2260200 1 26000 = = = = ( ) ( ) ( ) ( ) ( ) ( )jj.CjRZ .QLQLR pFCpF.LCC CC .V VQ H.C : L X XX X X X X S C 79674710200101432 17471 747100 102531014321052 10253101432 20010010253101432 11 1001010

4、25310100101432 1163 1 260 6666 0 00 62620 0 1 22620 = = =+ = = ( ) ( ) ( ) .21k0.5R,R, 0.5QQ, f22f 2 3 20 105 105552 3 1002 3 100 10150 105 2 22010501051432 1173 000 . 70 . 7 6 6 0 0 3 6 70 00 1 2620 电阻所以应并上= = = = = . f fQ f fQ HC : L . = gQ C ff CfCf : . . 0 700 070 22483 ( ) ( ) ( ) ( ) ( ) ( ) (

5、 ) ( )MHz.Qff .LRQ k RC CCCRRR k CLQR MHzLCf pF.CCC CCCC : C L . L Pi P i 481228 106412 2281080106411432 10885 885520 20202092010 920102020 1080100 6411031810801432 12 1 318202020 202020593 60 70 66 3 0 2 0 2 1 102 1 2 6 1 2 0 1 260 102 102 = = = = += += =+ = = =+=+= ) ) RZ3 0Z2 0Z1123 f1 f1 f1 = =

6、=解： ) ( ) ( ) ( ) ( ) ) ( ) ( ) ( ) ( ) ( ) ( ) ) ) ( ) ) ( ) ( ) ( ) ( ) ( ) ( ).j. j Z MZ jj CLjRZ pF.LC k Hz.R fQff . RR LQ k CRR LZ RMZ H RM pF.LCC H.LL : f . f f f P 843768010020 10183101432 1002010177101432 11015910143220 1 17710159109501432 115 22810 201022224 252020 101591014323 25101592020

7、10159 2020 101831014322 183101432 201 15910159101432 11 159101432 101133 266 2 2 2 0 11 1 26 66 20 2 10 222 2 623220 22 3 6 11 0070 66 11 10 11 1 2 6 111 1 266 2 2 0 11 60 1 1 626120 121 6 3 0 1 121 =+ = += += += = = =+ =+= =+ =+= = = = = = ( ) 100101410222 00 20101591050 10159153 3 6 7.0 0 1 11 23

8、6 = = = = f fQ MR RCR LR f P 解： ) ( ) ( ) ( ) ( )( ) ( ) ( ) ) ) 013.0200112221122 2005 10100103 2510102 40205 1010010 20510101163 22 0 7.0 67 1 0 1 67 1 0 1 267 11 2 0 1 267 2 2 0 11 =+=+= = = =+ =+= = Qf f R LQ R M kRR LR R MR : f a b f 5.75.2230 3021 10300 10101 1 21 1 8.111020001030014.325.22 11

9、 5.2225.1 1 10300 10101 1 21 1173 2 3 32 0 0 1 230 2 3 32 0 0 = = + = + = = = + = + = QQ Q Qf fQI I CQR Q Qf fQI I : ( ) = += = L HL CLL CL : 1253751 12 183 2 1 21 2 第三章高频小信号放大器 5 10250 1050501 50 1 ,50 12.1 10250 1020501 50 1 ,20 49 10250 10501 50 1 ,154 2 6 620 0 2 6 620 0 2 6 62 0 0 = + = + = = +

10、 = + = = + = + = T T T f f MHzf f f MHzf f f MHzf 当 当 解：当 ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )mSj.j.j ba j bagrCj ba j baCjggrCjgy mSj. jba j bagy mSj. j.jba j baCjgy mS.j. . j.j ba j baCjgy rCb .gra pF. .fgC mSrg mS.Ig mbbcbcbcbmbbcbc eo e mf e cbcbr e ebeb

11、i e bbeb ebbb T meb eb m Eeb 68.0049.0101 1.01107.37701103101432 1 733.3327.37101 1.01107.37 187.00187.0101 1.01103101432 4118950 101 1.01102410143210754.0 10701024101432 11075407011 24102501432 107372 73710754050 754015026 112674 22 31 27 2222 22 3 22 22 1 27 22 22 1 273 22 1 27 3 6 3 30 0 += + + +

12、= =+ =+= =+ + += += + += + += = +=+= = = = =+=+= 解： ( )( ) ( )( ) 4 1 2 4 1 4 2 70 1010 04 2 104 010 04 1 704 070 12 110 124 1104 2 2 1104210124 2 12422124 284 = = = += = += m m m m . r m. m . m v o v m. m . m v o v f fK Q ff ffQA A Q ff ffQA A 故 得令 得解：令 ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 1 1031010

13、45 952110830081020010286021 83008250 1020025010237 9522 58854t a n2t a n 43110031611 6570316 107102 316104107102105228 11 3151312 312105228 1045250250 522810286041102004110237 237104100107102 11 25020525020594 33 26662 2 626 21 22 22 0 60 70 6660 22 6 321 6 2 6 2 62221 66 00 1 3 4 52 1 3 2 31 +=+= +

14、=+= =+= = = = = = = = = =+=+= = = . yy ggggS Sp gpgg QQK MH.Qff .LgQ AA g yppA Sgpgpgg SLQg .NNp.NNp r ef e Lo ei es i ep L oor ef e L Z L . L v op o f e v o i eo ep p 解： ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( )( ) ( ) 7221698266804238225025 668042479 47961044 44547821

15、2 2 259044546104422 61044 12 225 6519744541221224 3822502578213 445410158010410710143222 78211580 24383030 1580150300820301003701 0370104107101432100 111104 44 44 4 70 70 7070 4 1 7070 4 1 704 1 470 44 4 36260070 2221 222 2 2 1 5 6600 -.AA AA f fAA k Hz.ff k Hz.ff k Hzff AA k HzfLgf .g yppA mS.gpgpR

16、gg mS.LQg v ov o v ov o . .v ov o v ov o . f e v o i eo ep p = = = = = = = = = =+= =+=+= = 解： ( ) ( ) ( ) ( ) 不能满足 解： 9.1K 522106250110511432 12 1 625011830500114 r 0 . 1 1 22620 221 = + + + = 为奇数 为偶数 当 当解： n nngVtt dntgVI gVtt dgVI gVtt dgVI tnIi t ttgVi mmn mm mm n n m 0 1 12c osc os1 2 1c os1 1c

17、os 2 1 c os 0c os0 0c osc os135 2 21 0 0 ( )( ) ( ),3,2,1ktc os2k 12k 1gV4gV2i 0c os0 0c osc osi 0c os0 0c osc os iii155 0 1k 2 1k mm D2D1 D2D1 =+= = += = t ttgV t ttgVi mm 当 当 当 当 解： ( )( ) ( ) ( ),3,2,1k 14 2c oss i n2 14 2c os2s i n12i s i ns i n10s i ns i n1 00s i ns i n1165 1 2 0 1 2 00 0000 00

18、 = += +=+ = + + + + + + = = =+=+= =+= k59.029 0 0 02 KRR 0 . 9co sK 0 . 51 5 0 06 0 0 0 1 0 01 4.33RR3 F2 0CF2 6.02 0 0 03 0 01 4.32 1r1C F0 1.0CCF0 1 8 7.03 0 0 01 4.329 0 0 03.0 3.01Rm m-1C 3.0m3193RRmk326 265.1rR rRRR 5 k.1R6 kRR1 0151Rk1 05RRR2 09 d i d d 33 d e i 2m i n e 21 2 m a xa 2a aa i 22

19、 i 221 122121 ( ) 1 5 3.0 4 7 0 0 2 1 08 4.51 0 03.08 4.55.2 31 0 0 5.2 32 04 6 52 8 4.51 0 0 1 02 0 01 04 6 51 4.322 19 622240 34 7.0 0 123 0 0 = = = = = i d Po eP L L P g GgpGQQ p f fQ SQCG 解： ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) 时，有失真。只产生相移；当时，当 有失真。 时，当 只影响输出幅度。无失真， 时，当 解： 1010 0101LS 010101 0011 111 0101LS10 01L01LS10 0101 010101 0011 111 tc osVVkmR41v tc ostc osVkmV41 tc ost Vc oskmV21i tc osm V21v2 tc ostc osVVkmR21v tc osc osVVkmR21tc ostc osVVkmR41v tc ostc os tc ostc osVkmV41 tc ost Vt c osc oskmVi tt c osc osm Vv1249 = += += += += = =+= + += += =