Java 中 Future 的 get 方法超时会怎样?

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Java 中 Future 的 get 方法超时会怎样?

#Java 中 Future 的 get 方法超时会怎样?| 来源: 网络整理| 查看: 265

一、背景

很多 Java 工程师在准备面试时,会刷很多八股文,线程和线程池这一块通常会准备线程的状态、线程的创建方式,Executors 里面的一些工厂方法和为什么不推荐使用这些工厂方法,ThreadPoolExecutor 构造方法的一些参数和执行过程等。

工作中,很多人会使用线程池的 submit 方法 获取 Future 类型的返回值,然后使用 java.util.concurrent.Future#get(long, java.util.concurrent.TimeUnit) 实现“最多等多久”的效果。

但很多人对此的理解只停留在表面上,稍微问深一点点可能就懵逼了。

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比如,java.util.concurrent.Future#get(long, java.util.concurrent.TimeUnit) 超时之后,当前线程会怎样?线程池里执行对应任务的线程会有怎样的表现?

如果你对这个问题没有很大的把握,说明你掌握的还不够扎实。

最常见的理解就是,“超时以后,当前线程继续执行,线程池里的对应线程中断”,真的是这样吗?

二、模拟2.1 常见写法

下面给出一个简单的模拟案例:

代码语言:javascript复制package basic.thread; import java.util.concurrent.*; public class FutureDemo { public static void main(String[] args) throws ExecutionException, InterruptedException, TimeoutException { ExecutorService executorService = Executors.newFixedThreadPool(2); Future future = executorService.submit(() -> { try { demo(); } catch (InterruptedException e) { throw new RuntimeException(e); } }); String threadName = Thread.currentThread().getName(); System.out.println(threadName + "获取的结果 -- start"); Object result = future.get(100, TimeUnit.MILLISECONDS); System.out.println(threadName + "获取的结果 -- end :" + result); } private static String demo() throws InterruptedException { String threadName = Thread.currentThread().getName(); System.out.println(threadName + ",执行 demo -- start"); TimeUnit.SECONDS.sleep(1); System.out.println(threadName + ",执行 demo -- end"); return "test"; } }

输出结果:

代码语言:javascript复制main获取的结果 -- start pool-1-thread-1,执行 demo -- start Exception in thread "main" java.util.concurrent.TimeoutException at java.util.concurrent.FutureTask.get(FutureTask.java:205) at basic.thread.FutureDemo.main(FutureDemo.java:20) pool-1-thread-1,执行 demo -- end

我们可以发现:当前线程会因为收到 TimeoutException 而被中断,线程池里对应的线程“却”继续执行完毕。

2.2 尝试取消

我们尝试对未完成的线程进行取消,发现 Future#cancel 有个 boolean 类型的参数。

代码语言:javascript复制 /** * Attempts to cancel execution of this task. This attempt will * fail if the task has already completed, has already been cancelled, * or could not be cancelled for some other reason. If successful, * and this task has not started when {@code cancel} is called, * this task should never run. If the task has already started, * then the {@code mayInterruptIfRunning} parameter determines * whether the thread executing this task should be interrupted in * an attempt to stop the task. * * After this method returns, subsequent calls to {@link #isDone} will * always return {@code true}. Subsequent calls to {@link #isCancelled} * will always return {@code true} if this method returned {@code true}. * * @param mayInterruptIfRunning {@code true} if the thread executing this * task should be interrupted; otherwise, in-progress tasks are allowed * to complete * @return {@code false} if the task could not be cancelled, * typically because it has already completed normally; * {@code true} otherwise */ boolean cancel(boolean mayInterruptIfRunning);

看源码注释我们可以知道:

当设置为 true 时,正在执行的任务将被中断(interrupted);

当设置为 false 时,如果任务正在执行中,那么仍然允许任务执行完成。

2.2.1 cancel(false)

此时,为了不让主线程因为超时异常被中断,我们 try-catch 包起来。

代码语言:javascript复制package basic.thread; import org.junit.platform.commons.util.ExceptionUtils; import java.util.concurrent.*; public class FutureDemo { public static void main(String[] args) throws ExecutionException, InterruptedException, TimeoutException { ExecutorService executorService = Executors.newFixedThreadPool(2); Future future = executorService.submit(() -> { try { demo(); } catch (InterruptedException e) { throw new RuntimeException(e); } }); String threadName = Thread.currentThread().getName(); System.out.println(System.currentTimeMillis() + "," + threadName + "获取的结果 -- start"); try { Object result = future.get(100, TimeUnit.MILLISECONDS); System.out.println(System.currentTimeMillis() + "," + threadName + "获取的结果 -- end :" + result); } catch (Exception e) { System.out.println(System.currentTimeMillis() + "," + threadName + "获取的结果异常:" + ExceptionUtils.readStackTrace(e)); } future.cancel(false); System.out.println(System.currentTimeMillis() + "," + threadName + "获取的结果 -- cancel"); } private static String demo() throws InterruptedException { String threadName = Thread.currentThread().getName(); System.out.println(System.currentTimeMillis() + "," + threadName + ",执行 demo -- start"); TimeUnit.SECONDS.sleep(1); System.out.println(System.currentTimeMillis() + "," + threadName + ",执行 demo -- end"); return "test"; } }

结果:

代码语言:javascript复制1653751759233,main获取的结果 -- start 1653751759233,pool-1-thread-1,执行 demo -- start 1653751759343,main获取的结果异常:java.util.concurrent.TimeoutException at java.util.concurrent.FutureTask.get(FutureTask.java:205) at basic.thread.FutureDemo.main(FutureDemo.java:23) 1653751759351,main获取的结果 -- cancel 1653751760263,pool-1-thread-1,执行 demo -- end

我们发现,线程池里的对应线程在 cancel(false) 时,如果已经正在执行,则会继续执行完成。

2.2.2 cancel(true)代码语言:javascript复制package basic.thread; import org.junit.platform.commons.util.ExceptionUtils; import java.util.concurrent.*; public class FutureDemo { public static void main(String[] args) throws ExecutionException, InterruptedException, TimeoutException { ExecutorService executorService = Executors.newFixedThreadPool(2); Future future = executorService.submit(() -> { try { demo(); } catch (InterruptedException e) { System.out.println(System.currentTimeMillis() + "," + Thread.currentThread().getName() + ", Interrupted:" + ExceptionUtils.readStackTrace(e)); throw new RuntimeException(e); } }); String threadName = Thread.currentThread().getName(); System.out.println(System.currentTimeMillis() + "," + threadName + "获取的结果 -- start"); try { Object result = future.get(100, TimeUnit.MILLISECONDS); System.out.println(System.currentTimeMillis() + "," + threadName + "获取的结果 -- end :" + result); } catch (Exception e) { System.out.println(System.currentTimeMillis() + "," + threadName + "获取的结果异常:" + ExceptionUtils.readStackTrace(e)); } future.cancel(true); System.out.println(System.currentTimeMillis() + "," + threadName + "获取的结果 -- cancel"); } private static String demo() throws InterruptedException { String threadName = Thread.currentThread().getName(); System.out.println(System.currentTimeMillis() + "," + threadName + ",执行 demo -- start"); TimeUnit.SECONDS.sleep(1); System.out.println(System.currentTimeMillis() + "," + threadName + ",执行 demo -- end"); return "test"; } }

执行结果:

代码语言:javascript复制1653752011246,main获取的结果 -- start 1653752011246,pool-1-thread-1,执行 demo -- start 1653752011347,main获取的结果异常:java.util.concurrent.TimeoutException at java.util.concurrent.FutureTask.get(FutureTask.java:205) at basic.thread.FutureDemo.main(FutureDemo.java:24) 1653752011363,pool-1-thread-1, Interrupted:java.lang.InterruptedException: sleep interrupted at java.lang.Thread.sleep(Native Method) at java.lang.Thread.sleep(Thread.java:340) at java.util.concurrent.TimeUnit.sleep(TimeUnit.java:386) at basic.thread.FutureDemo.demo(FutureDemo.java:36) at basic.thread.FutureDemo.lambda$main$0(FutureDemo.java:14) at java.util.concurrent.Executors$RunnableAdapter.call(Executors.java:511) at java.util.concurrent.FutureTask.run(FutureTask.java:266) at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1149) at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:624) at java.lang.Thread.run(Thread.java:748) 1653752011366,main获取的结果 -- cancel

可以看出,此时,如果目标线程未执行完,那么会收到 InterruptedException ,被中断。

当然,如果此时不希望目标线程被中断,可以使用 try-catch 包住,再执行其他逻辑。

代码语言:javascript复制package basic.thread; import org.junit.platform.commons.util.ExceptionUtils; import java.util.concurrent.*; public class FutureDemo { public static void main(String[] args) throws ExecutionException, InterruptedException, TimeoutException { ExecutorService executorService = Executors.newFixedThreadPool(2); Future future = executorService.submit(() -> { demo(); }); String threadName = Thread.currentThread().getName(); System.out.println(System.currentTimeMillis() + "," + threadName + "获取的结果 -- start"); try { Object result = future.get(100, TimeUnit.MILLISECONDS); System.out.println(System.currentTimeMillis() + "," + threadName + "获取的结果 -- end :" + result); } catch (Exception e) { System.out.println(System.currentTimeMillis() + "," + threadName + "获取的结果异常:" + ExceptionUtils.readStackTrace(e)); } future.cancel(true); System.out.println(System.currentTimeMillis() + "," + threadName + "获取的结果 -- cancel"); } private static String demo() { String threadName = Thread.currentThread().getName(); System.out.println(System.currentTimeMillis() + "," + threadName + ",执行 demo -- start"); try { TimeUnit.SECONDS.sleep(1); } catch (InterruptedException e) { System.out.println(System.currentTimeMillis() + "," + threadName + ",执行 demo 被中断,自动降级"); } System.out.println(System.currentTimeMillis() + "," + threadName + ",执行 demo -- end"); return "test"; } }

执行结果:

代码语言:javascript复制1653752219803,main获取的结果 -- start 1653752219803,pool-1-thread-1,执行 demo -- start 1653752219908,main获取的结果异常:java.util.concurrent.TimeoutException at java.util.concurrent.FutureTask.get(FutureTask.java:205) at basic.thread.FutureDemo.main(FutureDemo.java:19) 1653752219913,main获取的结果 -- cancel 1653752219914,pool-1-thread-1,执行 demo 被中断,自动降级 1653752219914,pool-1-thread-1,执行 demo -- end三、回归源码

我们直接看 java.util.concurrent.Future#get(long, java.util.concurrent.TimeUnit) 的源码注释,就可以清楚地知道各种情况的表现:

代码语言:javascript复制 /** * Waits if necessary for at most the given time for the computation * to complete, and then retrieves its result, if available. * * @param timeout the maximum time to wait * @param unit the time unit of the timeout argument * @return the computed result * @throws CancellationException if the computation was cancelled * @throws ExecutionException if the computation threw an * exception * @throws InterruptedException if the current thread was interrupted * while waiting * @throws TimeoutException if the wait timed out */ V get(long timeout, TimeUnit unit) throws InterruptedException, ExecutionException, TimeoutException;

我们还可以选取几个常见的实现类,查看下实现的基本思路:

java.util.concurrent.FutureTask#get(long, java.util.concurrent.TimeUnit)

代码语言:javascript复制 public V get(long timeout, TimeUnit unit) throws InterruptedException, ExecutionException, TimeoutException { if (unit == null) throw new NullPointerException(); int s = state; if (s


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