题解

您所在的位置:网站首页 简单计算器js 题解

题解

2023-03-15 18:06| 来源: 网络整理| 查看: 265

题解 | #简易计算器#

简易计算器

https://www.nowcoder.com/practice/8237298fd1354cdaabd04796280cc90e

var Calculator = { init: function () { var that = this; if (!that.isInited) { that.isInited = true; // 保存操作信息 // total: Number, 总的结果 // next: String, 下一个和 total 进行运算的数据 // action: String, 操作符号 that.data = {total: 0, next: '', action: ''}; that.bindEvent(); } }, bindEvent: function () { var that = this; // 请补充代码:获取 .cal-keyboard 元素 var keyboardEl = document.querySelector(".cal-keyboard"); keyboardEl && keyboardEl.addEventListener('click', function (event) { // 请补充代码:获取当前点击的dom元素 var target = event.target; // 请补充代码:获取target的 data-action 值 var action = target.getAttribute("data-action"); // 请补充代码:获取target的内容 var value = target.innerHTML; if (action === 'num' || action === 'operator') { that.result(value, action === 'num'); } }); }, result: function (action, isNum) { var that = this; var data = that.data; if (isNum) { data.next = data.next === '0' ? action : (data.next + action); !data.action && (data.total = 0); } else if (action === '清空') { // 请补充代码:设置清空时的对应状态 data.total = 0; data.next = ''; data.action = ''; } else if (action === '=') { if (data.next || data.action) { data.total = that.calculate(data.total, data.next, data.action); data.next = ''; data.action = ''; } } else if (!data.next) { data.action = action; } else if (data.action) { data.total = that.calculate(data.total, data.next, data.action); data.next = ''; data.action = action; } else { data.total = +data.next || 0; data.next = ''; data.action = action; } // ���补充代码:获取 .origin-value 元素 var valEl = document.querySelector(".origin-value"); valEl && (valEl.innerHTML = data.next || data.total || '0'); }, calculate: function (n1, n2, operator) { n1 = +n1 || 0; n2 = +n2 || 0; if (operator === '÷') { // 请补充代码:获取除法的结果 if (n2 === 0) return 0 return parseFloat((n1 / n2).toFixed(2)); } else if (operator === 'x') { // 请补充代码:获取乘法的结果 return parseFloat((n1 * n2).toFixed(2)); } else if (operator === '+') { // 请补充代码:获取加法的结果 return parseFloat((n1 + n2).toFixed(2)); } else if (operator === '-') { // 请补充代码:获取减法的结果 return parseFloat((n1 - n2).toFixed(2)); } } };

注意!此信息未认证,请谨慎判断信息的真实性!

提示


【本文地址】


今日新闻


推荐新闻


    CopyRight 2018-2019 办公设备维修网 版权所有 豫ICP备15022753号-3