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///++ 四、字典 Dic 【键-值对】 (var可变，let不可变)
///++ 四、字典 Dic 【键-值对】 (var可变，let不可变)
func yeDic()
{
//--- 0. 均为空Dic：
var eDic01 = Dictionary()
var eDic02 = [String:Int]()
var eDic03:Dictionary = [:]
var eDic04 = Dictionary()
var eDic05 = [String:Any]()
//--- 1.
let vDic0:Dictionary = ["Key0":"ValueStr", "Key1":15]
let vDic00:[String:Any] = ["Key0":"ValueStr", "Key1":15]
// [String:Any] 等同于 Dictionary
let vDic1 = ["Key0":"ValueStr", "Key1":15] as [String:Any] //转
let vDic2 = ["Key0":"vGoStr", "Key1":"vFarStr"] //仅一种类型可推导
let eDic3 = ["eKey0": 5, "eKey1":15]
print("字典的元素个数: \(eDic3.count)")
print("字典是否为空: \(eDic3.isEmpty)")
//--- 2. Dic的 增 删 改 查:
var eDic2 = [String:Any]() //Dictionary()
// 2.1 增、改 : 有此Key则更新,无则增加;（两种方式）
eDic2["Key0"] = "Value"
eDic2["Key1"] = 15
eDic2["Key0"] = "Gofar" //方式一；
let eV42a = eDic2.updateValue("WXL", forKey: "Key0")//方式二, 返回可选类型;
// 2.2 删
eDic2["Key0"] = nil //方式一；
let eV43a = eDic2.removeValue(forKey: "Key1") //方式二, 返回可选类型;
// 2.3 查
//print(eDic5["Key0"] as! String) //Any型转String,vDicM0["Key0"]是Any类型,
//--- 3. Dic 遍历：
for (eK, eValue) in eDic2{ //直接解包得到Key-Value;
print(" Dic 遍历1. 同时遍历Key-Value值:key=\(eK), 值=\(eValue) ")
}
for eK in eDic2.keys.sorted() { // 按key的排序 遍历;
print(" Dic 遍历2. 按Key排序 key=\(eK), 值=\(eDic2[eK]) ")
}
for eK in eDic2.keys{
print(" Dic 遍历3. Key值: \(eK) ")
}
for eValue in eDic2.values{
print(" Dic 遍历4. Value值: \(eValue) ")
}
//--- 4. Dic 合并：（注意类型）【字典不可直接+】
var eDic4a = Dictionary()
// 4.1 合并：（注意类型）【字典不可直接+】
//let vDicM2 = vDicM0 + vDicM1 //XXX
for (eKey,eValue) in eDic4a{ //将 eDic4a 加到 eDic2 中：
eDic2[eKey] = eValue
}
// 4.2 merge 合并:
var eDic7 = ["k1":5, "k2":15]
eDic7.merge(["k1":25, "k6":35]) { eOld, _ in
eOld
} // 当有相同的key时用原来的值; ["k1": 5, "k6": 35, "k2": 15]
print("字典 合并1: \(eDic7)")
eDic7.merge(["k1":55, "k7":77]) { _, eNew in
eNew
} //当有相同的key时用新的值; ["k2": 15, "k6": 35, "k7": 77, "k1": 55]
print("字典 合并2: \(eDic7)")
//--- 5. 保持顺序 KeyValuePairs: (字典本身数无序的,在扩容之前位置数稳定的)
var eDic8 = ["k1":"value1", "k2":"value2", "k3":"Tye"]
let eV8 = eDic8.firstIndex(where: { // 查找到第一个符合条件的为止;
$0.value.hasPrefix("value")
}) // 得到的数可选类型;
let eV9 = eDic8.firstIndex { (key: String, value: String) in
value.hasPrefix("value")
}// 得到的数可选类型; firstIndex 查找到第一个符合条件的为止;
//print("---***888: \(eV8)") // eV8 与 eV9 是一样的，只是写法不一样;
//eDic8["k9"] = "DiTye" //在firstIndex查找完后,加入元素(扩容了)，eDic8[i]会报错 [因为eV9对应的位置就变了]
if let i = eV9{ //let i = eV8 解包可选类型;
print("条件筛选的 \(eDic8[i]) ") //(key: "k1", value: "value1")
}
//
var eDic9 : KeyValuePairs = ["k1":5, "k2":7, "k3":9]
print("字典 保持顺序:\(eDic9.first!)")//取第一对键值对:(key: "k1", value: 5)
}
///++ Dic 字典 End;
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字典Dic的操作
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//--- Dictionary
func yeSwift(){
var airports : Dictionary = ["DUB": "Dublin", "TYO": "Tokyo"]
var firstStudent = ["Name": "Peter", "Age": "12"]
//var firstStudent = ["Name": "Peter", "Age": 12]
var secondStudent : Dictionary = ["Name": "Peter", "Age": 25]
secondStudent["Name"]
secondStudent["Age"]
secondStudent["Name"] = "John"
secondStudent["Age"] = 18
secondStudent["Gender"] = "Male"
secondStudent.count
secondStudent.description
secondStudent.isEmpty
secondStudent.updateValue("Jerry", forKey: "Name")
secondStudent.popFirst()
secondStudent.removeValue(forKey: "Gender")
secondStudent
secondStudent.removeAll()
firstStudent.first?.key
firstStudent.first?.value
firstStudent.reversed()
for key in firstStudent.keys
{
print(">>>>>\(key)")
}
for value in firstStudent.values
{
print(">>>>>\(value)")
}
for (key, value) in firstStudent
{
print(">>>>>\(key): \(value)")
}
var dicpts : Dictionary = ["iː":"yi", "i,ɪ":"x", "e":"x", "æ":"x", "ɜː":"x", "ə":"x", "ʌ":"x", "uː":"x", "u,ʊ":"x", "ɔː":"x", "ɔ,ɒ":"x", "ɑː":"x", "ei,eɪ":"x", "ai,aɪ":"x", "ɔi,ɔɪ":"x", "au,aʊ":"x", "əu,əʊ":"x", "iə,ɪə":"x", "eə,ɛə":"x", "uə,ʊə":"x", "p":"x", "t":"x", "k":"x", "b":"x", "d":"x", "ɡ":"x", "f":"x", "s":"x", "ʃ":"x", "θ":"x", "h":"x", "v":"x", "z":"x", "ʒ":"x", "ð":"x", "r":"x", "tʃ":"x", "tr":"x", "ts":"x", "dʒ":"x", "dr":"x", "dz":"x", "m":"x", "n":"x", "ŋ":"x", "l":"x", "j":"x", "w":"x"]
let keys = Array(dicpts.keys).sorted()
print(keys[0])
}
//--- 2. Dictionary
func yeSwift(){
let laptops = ["Acer Aspire 5 Slim Laptop": 364.99, "Lenovo Legion 5 Gaming Laptop": 999.99, "HP 15 Laptop": 629.00, "Apple MBP 15-inch Laptop": 1_399.99];
let filteredLaptops = laptops.filter { $0.value > 800.00 }
print("filteredLaptops: \(filteredLaptops)")
let filteredLaptops2 = laptops.filter { $0.key.hasPrefix("Apple") }
print("filteredLaptops: \(filteredLaptops2)")
let groupedLaptops = Dictionary(grouping: laptops.keys) { $0.first! }
print("groupedLaptops: \(groupedLaptops)")
var devices = ["iPhone", "iPad", "iWatch", "iPhone"]
var devicesCounts = [String: Int]()
for device in devices
{
devicesCounts[device, default: 0] += 1
}
print("devicesCounts: \(devicesCounts)")
let scores = ["Math": 89,
"Physics": 88,
"Geography": 78,
"History": 92]
let doubleScores = scores.map { $0.value * 2 }
let roundedCities = scores.mapValues { score -> String in
"Your score is \(score)."
}
print(doubleScores)
print(roundedCities)
let scores2 = ["Math": "89",
"Physics": "88",
"Geography": "none",
"History": nil]
let compactMapValues = scores2.compactMapValues { $0}
print(compactMapValues)
let compactMapValues2 = scores2.compactMapValues { Int($0 ?? "") }
print(compactMapValues2)
}
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