python:将数字转换成用英文表达的程序 |
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前几天无意中看到了一篇文章列了很多数字的英文表达方式(http://blog.csdn.net/sun7545526/article/details/8122416),正好这段时间在学习python,所以写了个简单的程序用来将数字翻译成英文的表达方式,例如输入123,返回 one hundred and twenty-three ,目前该程序可以表示的范围为0-999,999,999,999.由于本人是个python新手,所以如果用的不完善的地方,还请帮忙改正 ''' convert number to string, number range is 0-999,999,999,999 and must be integer Created on 2012-10-31 @author: Eric ''' import locale; NUMBER_CONSTANT = {0:"zero ", 1:"one", 2:"two", 3:"three", 4:"four", 5:"five", 6:"six", 7:"seven", 8:"eight", 9:"nine", 10:"ten", 11:"eleven", 12:"twelve", 13:"thirteen", 14:"fourteen", 15:"fifteen", 16:"sixteen", 17:"seventeen", 18:"eighteen", 19:"nineteen" }; IN_HUNDRED_CONSTANT = {2:"twenty", 3:"thirty", 4:"forty", 5:"fifty", 6:"sixty", 7:"seventy", 8:"eighty", 9:"ninety"} BASE_CONSTANT = {0:" ", 1:"hundred", 2:"thousand", 3:"million", 4:"billion"}; #supported number range is 1-n billion; def translateNumberToEnglish(number): if str(number).isnumeric(): if str(number)[0] == '0' and len(str(number)) > 1: return translateNumberToEnglish(int(number[1:])); if int(number) < 20: return NUMBER_CONSTANT[int(number)]; elif int(number) < 100: if str(number)[1] == '0': return IN_HUNDRED_CONSTANT[int(str(number)[0])]; else: return IN_HUNDRED_CONSTANT[int(str(number)[0])] + "-" + NUMBER_CONSTANT[int(str(number)[1])]; else: locale.setlocale(locale.LC_ALL, "English_United States.1252"); strNumber = locale.format("%d" , number, grouping=True); numberArray = str(strNumber).split(","); stringResult = ""; groupCount = len(numberArray) + 1; for groupNumber in numberArray: if groupCount > 1 and groupNumber[0:] != "000": stringResult += str(getUnderThreeNumberString(str(groupNumber))) + " "; else: break; groupCount -= 1; if groupCount > 1: stringResult += BASE_CONSTANT[groupCount] + ","; endPoint = len(stringResult) - len(" hundred,"); #return stringResult[0:endPoint]; return stringResult; else: print("please input a number!"); #between 0-999 def getUnderThreeNumberString(number): if str(number).isnumeric() and len(number) < 4: if len(number) < 3: return translateNumberToEnglish(int(number)); elif len(number) == 3 and number[0:] == "000": return " "; elif len(number) == 3 and number[1:] == "00": return NUMBER_CONSTANT[int(number[0])] + " " + BASE_CONSTANT[1]; else: return NUMBER_CONSTANT[int(number[0])] + " " + BASE_CONSTANT[1] + " and " + translateNumberToEnglish((number[1:])); else: print("number must below 1000"); def testTranslateNumberToEnglish(): print("0: " + translateNumberToEnglish(0)); print("9: " + translateNumberToEnglish(9)); print("33: " + translateNumberToEnglish(33)); print("40: " + translateNumberToEnglish(40)); print("100: " + translateNumberToEnglish(100)); print("103: " + translateNumberToEnglish(103)); print("123: " + translateNumberToEnglish(123)); print("1,121,912 " + translateNumberToEnglish(1121912)); print("211,121,900 " + translateNumberToEnglish(211121900)); print("11,000,000 " + translateNumberToEnglish(11000000)); print("1,111,121,912 " + translateNumberToEnglish(111121912)); print("2,211,121,900 " + translateNumberToEnglish(2211121900)); print("1,111,000,000 " + translateNumberToEnglish(1111000000)); if __name__ == '__main__': testTranslateNumberToEnglish();输出的结果为: 0: zero 9: nine 33: thirty-three 40: forty 100: one hundred 103: one hundred and three 123: one hundred and twenty-three 1,121,912 one million,one hundred and twenty-one thousand,nine hundred and twelve 211,121,900 two hundred and eleven million,one hundred and twenty-one thousand,nine hundred 11,000,000 eleven million, 1,111,121,912 one hundred and eleven million,one hundred and twenty-one thousand,nine hundred and twelve 2,211,121,900 two billion,two hundred and eleven million,one hundred and twenty-one thousand,nine hundred 1,111,000,000 one billion,one hundred and eleven million, |
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