python 制作CPU压力测试

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python 制作CPU压力测试

2023-09-19 04:38| 来源: 网络整理| 查看: 265

 

众所周知,反正弦函数asin有以下公式(如在计算器中是弧度制下):

\frac{\pi}{2}=arcsin\left ( 1 \right )

百度百科搜索三角函数公式,在泰勒展开式一节中有以下公式:

(doubleFact(2*k-1)/doubleFact(2*k))*(pow(x,2*k+1)/(2*k+1)) 其中arcsin写错了,(2k+1)!!应该是(2k-1)!! 另外x!!指双阶乘,不同于阶乘   双阶乘实现: def doubleFact(x): ans=1 for i in range(1,x+1): if i%2 == x%2: ans*=i return ans asin函数实现 def asin(x,t): answer=0 for k in range(0,t+1): a=(doubleFact(2*k-1)/doubleFact(2*k))*(pow(x,2*k+1)/(2*k+1)) print("k=%d,a=%s"%(k,a)) answer+=a

其中x为角度(弧度),t为计算次数。

注:代码奇慢无比,不要真正用来计算pi,又慢精度又不高,建议只用来编写CPU压力测试程序!

总代吗贴出来: # import math def doubleFact(x): ans=1 for i in range(1,x+1): if i%2 == x%2: ans*=i return ans def asin(x,t): answer=0 for k in range(0,t+1): a=(doubleFact(2*k-1)/doubleFact(2*k))*(pow(x,2*k+1)/(2*k+1)) print("k=%d,a=%s"%(k,a)) answer+=a return answer print(asin(1,100)*2)

计算结果:

k=0,a=1.0 k=1,a=0.16666666666666666 k=2,a=0.07500000000000001 k=3,a=0.04464285714285714 k=4,a=0.030381944444444444 k=5,a=0.022372159090909092 k=6,a=0.017352764423076924 k=7,a=0.013964843749999999 k=8,a=0.011551800896139705 k=9,a=0.009761609529194078 k=10,a=0.008390335809616815 k=11,a=0.007312525873598845 k=12,a=0.006447210311889649 k=13,a=0.005740037670841923 k=14,a=0.005153309682319904 k=15,a=0.004660143486915096 k=16,a=0.004240907093679363 k=17,a=0.003880964558837669 k=18,a=0.0035692053938259347 k=19,a=0.0032970595034734844 k=20,a=0.0030578216492580306 k=21,a=0.002846178401108942 k=22,a=0.00265787063820729 k=23,a=0.0024894486782468836 k=24,a=0.002338091892111975 k=25,a=0.0022014739737101384 k=26,a=0.002077661032518167 k=27,a=0.0019650336162772837 k=28,a=0.0018622264064031273 k=29,a=0.0017680811205154183 k=30,a=0.0016816093935831068 k=31,a=0.0016019632753514438 k=32,a=0.0015284115961225677 k=33,a=0.0014603208940791154 k=34,a=0.0013971399176302534 k=35,a=0.0013383869512751784 k=36,a=0.0012836393876290285 k=37,a=0.001232525098500017 k=38,a=0.0011847152561624392 k=39,a=0.0011399183307022236 k=40,a=0.0010978750465914472 k=41,a=0.001058354125872243 k=42,a=0.0010211486797106276 k=43,a=0.0009860731369833312 k=44,a=0.0009529606197429564 k=45,a=0.0009216606921836336 k=46,a=0.0008920374230917098 k=47,a=0.0008639677124658675 k=48,a=0.000837339841602712 k=49,a=0.0008120522129086703 k=50,a=0.0007880122513582057 k=51,a=0.0007651354441371649 k=52,a=0.0007433444987958959 k=53,a=0.0007225686033525614 k=54,a=0.0007027427743614913 k=55,a=0.0006838072810965503 k=56,a=0.0006657071357767537 k=57,a=0.000648391641245871 k=58,a=0.0006318139887619102 k=59,a=0.0006159308995984751 k=60,a=0.0006007023050422869 k=61,a=0.0005860910601175613 k=62,a=0.0005720626870011989 k=63,a=0.0005585851446315293 k=64,a=0.0005456286214729855 k=65,a=0.0005331653487922461 k=66,a=0.0005211694321385132 k=67,a=0.0005096166990104013 k=68,a=0.000498484560941636 k=69,a=0.0004877518884534234 k=70,a=0.000477398897508034 k=71,a=0.000467407046260082 k=72,a=0.00045775894104274026 k=73,a=0.00044843825064875664 k=74,a=0.0004394296280731444 k=75,a=0.00043071863897800795 k=76,a=0.0004222916962219453 k=77,a=0.0004141359998684339 k=78,a=0.0004062394821508707 k=79,a=0.00039859075692766545 k=80,a=0.00039117907320994984 k=81,a=0.0003839942723879085 k=82,a=0.00037702674882018997 k=83,a=0.000370267413484946 k=84,a=0.0003637076604213038 k=85,a=0.0003573393357169886 k=86,a=0.0003511547088217658 k=87,a=0.00034514644598773823 k=88,a=0.00033930758565660254 k=89,a=0.00033363151563102445 k=90,a=0.0003281119518825554 k=91,a=0.00032274291886219894 k=92,a=0.00031751873119201474 k=93,a=0.0003124339766271837 k=94,a=0.00030748350018788655 k=95,a=0.00030266238936928896 k=96,a=0.0002979659603459907 k=97,a=0.0002933897450945759 k=98,a=0.0002889294793644786 k=99,a=0.00028458109143332955 k=100,a=0.0002803406915883404 3.0292687382573695

还是不是很精确啊!

PS:花了0.002991199493408203秒,虽然看起来很快,但是10000次花了快5分钟呢!

C#实现(备忘) using System; namespace CSharp_CountPi { class Program { static long doubleFact(int x) { long ans = 1; for (int i = 1; i


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