写出sql语句取出每门功课成绩最好的学生数据(面试题)

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写出sql语句取出每门功课成绩最好的学生数据(面试题)

2024-06-08 22:57| 来源: 网络整理| 查看: 265

在笔试中一般都会碰到书写sql语句的题目,上次去面试就碰到了,所以在这里总结一些。

创建表语句

SET ANSI_NULLS ONGOSET QUOTED_IDENTIFIER ONGOSET ANSI_PADDING ONGOCREATE TABLE [dbo].[stuscore] ( [name] [varchar](50) COLLATE Chinese_PRC_CI_AS NULL, [subject] [varchar](50) COLLATE Chinese_PRC_CI_AS NULL, [score] [int] NULL, [stuid] [int] NULL) ON [PRIMARY] GO SET ANSI_PADDING OFF

插入数据

insert into dbo.stuscore values ('张三','数学',89,1); insert into dbo.stuscore values ('张三','语文',80,1); insert into dbo.stuscore values ('张三','英语',70,1); insert into dbo.stuscore values ('李四','数学',90,2); insert into dbo.stuscore values ('李四','语文',70,2); insert into dbo.stuscore values ('李四','英语',80,2);

查询语句

select * from dbo.stuscore

问题:

1.计算每个人的总成绩并排名(要求显示字段:姓名,总成绩)

select name,SUM(score) as allscore from dbo.stuscore group by name order by allscore;

2.计算每个人的总成绩并排名(要求显示字段: 学号,姓名,总成绩) 

select stuid,name,SUM(score) as allscore from dbo.stuscore group by name,stuid order by allscore;

3.计算每个人单科的最高成绩(要求显示字段: 学号,姓名,课程,最高成绩)

select t1.stuid,t1.name,t1.subject,t1.score from stuscore t1, (select stuid,max(score) as maxscore from stuscore group by stuid) t2 where t1.stuid=t2.stuid and t1.score=t2.maxscore;

4.计算每个人的平均成绩(要求显示字段: 学号,姓名,平均成绩)

select stuid,name,AVG(score) avgscore from dbo.stuscore group by stuid,name;

5.列出各门课程成绩最好的学生(要求显示字段: 学号,姓名,科目,成绩) 

select t1.stuid,t1.name,t1.subject,t1.score from stuscore t1,( select subject,MAX(score) as maxscore from stuscore group by subject)t2 where t1.subject = t2.subject and t1.score = t2.maxscore;

6.列出各门课程成绩最好的两位学生(要求显示字段: 学号,姓名,科目,成绩) 

select t1.* from stuscore t1 where t1.stuid in ( select top 2 stuid from stuscore where subject = t1.subject order by score desc) order by t1.subject;

9.列出数学成绩的排名(要求显示字段:学号,姓名,成绩,排名)

select stuid,name,score, (select count(*) from stuscore t1 where subject ='数学' and t1.score > t2.score)+1 as 名次 from stuscore t2 where subject='数学' order by score desc;

更全面的请点击:https://blog.csdn.net/javakakayi/article/details/65628024?utm_source=copy 

 

 



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