WGS84坐标系转火星坐标系

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WGS84坐标系转火星坐标系

2023-03-27 11:29| 来源: 网络整理| 查看: 265

详情见https://on4wp7.codeplex.com/SourceControl/changeset/view/21483#353936

from __future__ import division from math import pi,sqrt,sin,cos # a python binding of https://on4wp7.codeplex.com/SourceControl/changeset/view/21483#353936 # Krasovsky 1940 # # a = 6378245.0, 1/f = 298.3 # b = a * (1 - f) # ee = (a^2 - b^2) / a^2 a = 6378245.0 ee = 0.00669342162296594323 # World Geodetic System ==> Mars Geodetic System def transform(wgLat, wgLon): """ transform(latitude,longitude) , WGS84 return (latitude,longitude) , GCJ02 """ if (outOfChina(wgLat, wgLon)): mgLat = wgLat mgLon = wgLon return dLat = transformLat(wgLon - 105.0, wgLat - 35.0) dLon = transformLon(wgLon - 105.0, wgLat - 35.0) radLat = wgLat / 180.0 * pi magic = sin(radLat) magic = 1 - ee * magic * magic sqrtMagic = sqrt(magic) dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi) dLon = (dLon * 180.0) / (a / sqrtMagic * cos(radLat) * pi) mgLat = wgLat + dLat mgLon = wgLon + dLon return mgLat,mgLon def outOfChina(lat, lon): if (lon < 72.004 or lon > 137.8347): return True if (lat < 0.8293 or lat > 55.8271): return True return False def transformLat(x, y): ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y + 0.2 * sqrt(abs(x)) ret += (20.0 * sin(6.0 * x * pi) + 20.0 * sin(2.0 * x * pi)) * 2.0 / 3.0 ret += (20.0 * sin(y * pi) + 40.0 * sin(y / 3.0 * pi)) * 2.0 / 3.0 ret += (160.0 * sin(y / 12.0 * pi) + 320 * sin(y * pi / 30.0)) * 2.0 / 3.0 return ret def transformLon(x, y): ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1 * sqrt(abs(x)) ret += (20.0 * sin(6.0 * x * pi) + 20.0 * sin(2.0 * x * pi)) * 2.0 / 3.0 ret += (20.0 * sin(x * pi) + 40.0 * sin(x / 3.0 * pi)) * 2.0 / 3.0 ret += (150.0 * sin(x / 12.0 * pi) + 300.0 * sin(x / 30.0 * pi)) * 2.0 / 3.0 return ret if __name__ == "__main__": WGS84_Lat = 39.990205 WGS84_Long = 116.327847 print transform(WGS84_Lat,WGS84_Long)


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