如何向RESTful WCF服务传递和使用一个JSON参数?

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如何向RESTful WCF服务传递和使用一个JSON参数?

2023-04-14 19:45| 来源: 网络整理| 查看: 265

百度翻译此文   有道翻译此文 问题描述

I am a beginner at RESTful services.

I need to create an interface where the client needs to pass up to 9 parameters.

I would prefer to pass the parameters as a JSON object.

For instance if my JSON is:

'{ "age":100, "name":"foo", "messages":["msg 1","msg 2","msg 3"], "favoriteColor" : "blue", "petName" : "Godzilla", "IQ" : "QuiteLow" }'

And if I need to execute a server side method below in the end:

public Person FindPerson(Peron lookUpPerson) { Person found = null; // Implementation that finds the Person and sets 'found' return found; }

Question(s): How should I make the call from the client-side with the above JSON string? And how can I create a signature and implementation of the RESTful service method that

accepts this JSON, parses and deserializes it into Person object and calls / returns the FindPerson method's return value back to client? 推荐答案

If you want to create a WCF operation to receive that JSON input, you'll need to define a data contract which maps to that input. There are a few tools which do that automatically, including one which I wrote a while back at http://jsontodatacontract.azurewebsites.net/ (more details on how this tool was written at this blog post). The tool generated this class, which you can use:

// Type created for JSON at [System.Runtime.Serialization.DataContractAttribute()] public partial class Person { [System.Runtime.Serialization.DataMemberAttribute()] public int age; [System.Runtime.Serialization.DataMemberAttribute()] public string name; [System.Runtime.Serialization.DataMemberAttribute()] public string[] messages; [System.Runtime.Serialization.DataMemberAttribute()] public string favoriteColor; [System.Runtime.Serialization.DataMemberAttribute()] public string petName; [System.Runtime.Serialization.DataMemberAttribute()] public string IQ; }

Next, you need to define an operation contract to receive that. Since the JSON needs to go in the body of the request, the most natural HTTP method to use is POST, so you can define the operation as below: the method being "POST" and the style being "Bare" (which means that your JSON maps directly to the parameter). Notice that you can even omit the Method and BodyStyle properties, since "POST" and WebMessageBodyStyle.Bare are their default values, respectively).

[WebInvoke(Method = "POST", BodyStyle = WebMessageBodyStyle.Bare)] public Person FindPerson(Peron lookUpPerson) { Person found = null; // Implementation that finds the Person and sets 'found' return found; }

Now, at the method you have the input mapped to lookupPerson. How you will implement the logic of your method is up to you.

Update after comment

One example of calling the service using JavaScript (via jQuery) can be found below.

var input = '{ "age":100, "name":"foo", "messages":["msg 1","msg 2","msg 3"], "favoriteColor" : "blue", "petName" : "Godzilla", "IQ" : "QuiteLow" }'; var endpointAddress = "http://your.server.com/app/service.svc"; var url = endpointAddress + "/FindPerson"; $.ajax({ type: 'POST', url: url, contentType: 'application/json', data: input, success: function(result) { alert(JSON.stringify(result)); } }); 其他推荐答案

1-Add the WebGet attribute

_ _ Public Function YourFunch(inpt As String) As String

2-Use NewtonSoft to serialize/deserialize your json into your object (note the above just takes in String), NewtonSoft is much faster than the MS serializer.

use NewtonSoft for serialization http://json.codeplex.com/

3- your .svc file will contain Factory="System.ServiceModel.Activation.WebServiceHostFactory

4- your web.config will contain

...and...



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