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Oracle ROW
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转载☞：https://blog.csdn.net/qq_25221835/article/details/82762416 ROW_NUMBER 语法 语法格式：row_number() over(partition by 分组列 order by 排序列 desc) 解释row_number() over()分组排序功能： 在使用 row_number() over()函数时候，over()里头的分组以及排序的执行晚于 where 、group by、 order by 的执行。 示例1表数据： create table TEST_ROW_NUMBER_OVER( id varchar(10) not null, name varchar(10) null, age varchar(10) null, salary int null ); select * from TEST_ROW_NUMBER_OVER t; insert into TEST_ROW_NUMBER_OVER(id,name,age,salary) values(1,'a',10,8000); insert into TEST_ROW_NUMBER_OVER(id,name,age,salary) values(1,'a2',11,6500); insert into TEST_ROW_NUMBER_OVER(id,name,age,salary) values(2,'b',12,13000); insert into TEST_ROW_NUMBER_OVER(id,name,age,salary) values(2,'b2',13,4500); insert into TEST_ROW_NUMBER_OVER(id,name,age,salary) values(3,'c',14,3000); insert into TEST_ROW_NUMBER_OVER(id,name,age,salary) values(3,'c2',15,20000); insert into TEST_ROW_NUMBER_OVER(id,name,age,salary) values(4,'d',16,30000); insert into TEST_ROW_NUMBER_OVER(id,name,age,salary) values(5,'d2',17,1800); 依次排序：对查询结果进行排序（无分组） select id,name,age,salary,row_number()over(order by salary desc) rn from TEST_ROW_NUMBER_OVER t结果
根据id分组排序 select id,name,age,salary,row_number()over(partition by id order by salary desc) rank from TEST_ROW_NUMBER_OVER t 结果
找出每一组中序号为一的数据 select * from(select id,name,age,salary,row_number()over(partition by id order by salary desc) rank from TEST_ROW_NUMBER_OVER t) where rank '2011-07-22' |
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