mysql查询每个部门/班级前几名 |
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Employee 表包含所有员工信息，每个员工有其对应的 Id, salary 和 department Id 。 +----+-------+--------+--------------+ | Id | Name | Salary | DepartmentId | +----+-------+--------+--------------+ | 1 | Joe | 70000 | 1 | | 2 | Henry | 80000 | 2 | | 3 | Sam | 60000 | 2 | | 4 | Max | 90000 | 1 | | 5 | Janet | 69000 | 1 | | 6 | Randy | 85000 | 1 | +----+-------+--------+--------------+Department 表包含公司所有部门的信息。 +----+----------+ | Id | Name | +----+----------+ | 1 | IT | | 2 | Sales | +----+----------+编写一个 SQL 查询，找出每个部门工资前三高的员工。例如，根据上述给定的表格，查询结果应返回： +------------+----------+--------+ | Department | Employee | Salary | +------------+----------+--------+ | IT | Max | 90000 | | IT | Randy | 85000 | | IT | Joe | 70000 | | Sales | Henry | 80000 | | Sales | Sam | 60000 | +------------+----------+--------+select d.Name Department,e1.Name Employee,e1.Salary from Employee e1,Department d where e1.DepartmentId=d.Id and(select count(distinct e2.Salary) from Employee e2 where e2.DepartmentId=d.Id and e2.Salary>e1.Salary) |
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