https://blog.csdn.net/u013538664/article/details/37673711

       合并方法：            直接将两个矩阵合并：              A = [1,2,3,4];              B = [-1,-2,-3,-4];              C = zeros(1,size(B,2)+size(A,2));     %这句能够不要;              C = [A, B];

    2、一维数组交叉合并：        题目：            数组work1[x1,x2——,xn]，work2[y1,y2——,yn]。如今要生成一个数组work3，        work3中的数据为[x1,y1,x2,y2——,xn,yn];               合并方法一:            A = [1,2,3,4];            B = [-1,-2,-3,-4];            C = zeros(1,size(B,2)+size(A,2));            C(1:2:end) = A;            C(2:2:end) = B                       C =                 1    -1     2    -2     3    -3     4    -4

       解法二：            A = [1,2,3,4];            B = [-1,-2,-3,-4];            C=[A' B']';            C=reshape(C, 1, length(A)+length(B));                       C =                 1    -1     2    -2     3    -3     4    -4

       解法三：

           对于解法二改进：

           c=reshape([A;B],1,[])；

           这里要注意，仅仅能在v7以上的版本号才干使用此法。

       解法四：            A = [1,2,3,4];            B = [-1,-2,-3,-4];            C=kron(A,[1 0])+kron(B,[0 1]);                       C =                 1    -1     2    -2     3    -3     4    -4       非常多技巧。试总结以上的方案：           -------------------------------------           A = [1,2,3,4];           B = [-1,-2,-3,-4];           ----------------- 1 -----------------           C = zeros(1,size(B,2)+size(A,2));           C(1:2:end) = A;           C(2:2:end) = B;           C=C(:);           ------------------2 -----------------           C=[A' B']';           C=reshape(C, 1, length(A)+length(B));           ------------------3-------------------           c=reshape([A;B],1,[])           ------------------4-------------------           C=kron(A,[1 0])+kron(B,[0 1]);           --------------------------------------