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2023-11-13 22:55| 来源: 网络整理| 查看: 265

这边给大家介绍一下,String中是如何删除指定字符,博主粗略总结了11种方法,如果有不足或者遗漏希望读者能够不吝赐教。

作者:CoderPLDQ

https://blog.csdn.net/li767517488/article/details/64919194

第一种方法

通过循环从前往后遍历,如果不是要删除的字符则加到处理后的字符串中,代码如下:

public String deleteCharString0(String sourceString, char chElemData) { String deleteString = ""; for (int i = 0; i < sourceString.length(); i++) { if (sourceString.charAt(i) != chElemData) { deleteString += sourceString.charAt(i); } } return deleteString; }

第二种方法

通过循环确定要删除字符的位置索引,然后通过分割字符串的形式,将子字符串拼接,注意最后一段子字符串和源字符串中没有要删除字符的情况,代码如下:

public String deleteCharString1(String sourceString, char chElemData) { String deleteString = ""; int iIndex = 0; for (int i = 0; i < sourceString.length(); i++) { if (sourceString.charAt(i) == chElemData) { if (i > 0) { deleteString += sourceString.substring(iIndex, i); } iIndex = i + 1; } } if (iIndex 0) { deleteString += sourceString.substring(iIndex, tmpCount); } if (tmpCount != -1) { iIndex = tmpCount + 1; } } while (tmpCount != -1); if (iIndex = 0) { deleteString = sourceString.substring(tmpCount + 1, iIndex) + deleteString; } if (tmpCount != -1) { iIndex = tmpCount; } } while (tmpCount != -1); if (iIndex >= 0) { deleteString = sourceString.substring(0, iIndex) + deleteString; } return deleteString; }

第五种方法

通过采用正则的方式和replaceAll函数,本种方法要注意特殊字符,例如正则中的 “.”字符,需要对特殊字符进行转义,代码如下:

public String deleteCharString4(String sourceString, char chElemData) { String deleteString = ""; final String strTable = "|^$*+?.(){}\\"; String tmpRegex = "["; for (int i = 0; i < strTable.length(); i++) { if (strTable.charAt(i) == chElemData) { tmpRegex += "\\"; break; } } tmpRegex += chElemData + "]"; deleteString = sourceString.replaceAll(tmpRegex, ""); return deleteString; }

第六种方法

采用正则的方式将字符串分割成几个子字符串,再将子字符串进行拼接,代码如下:

public String deleteCharString5(String sourceString, char chElemData) { String deleteString = ""; final String strTable = "|^$*+?.(){}\\"; String tmpRegex = "["; for (int i = 0; i < strTable.length(); i++) { if (strTable.charAt(i) == chElemData) { tmpRegex += "\\"; break; } } tmpRegex += chElemData + "]"; String[] tmpStringArray = sourceString.split(tmpRegex); for (int i = 0; i < tmpStringArray.length; i++) { deleteString += tmpStringArray[i]; } return deleteString; }

第七种方法

将字符编程可读序列,在通过 String 类中的方法替换,代码如下:

public String deleteCharString6(String sourceString, char chElemData) { String tmpString = ""; tmpString += chElemData; tmpString.subSequence(0, 0); String deleteString = ""; deleteString = sourceString.replace(tmpString, deleteString.subSequence(0, 0)); return deleteString; }

第八种方法

把原字符串转化为字符数组,然后原理与直接插入排序原理类似,代码如下:

public String deleteCharString7(String sourceString, char chElemData) { String deleteString = ""; char[] Bytes = sourceString.toCharArray(); int iSize = Bytes.length; for (int i = Bytes.length - 1; i >= 0; i--) { if (Bytes[i] == chElemData) { for (int j = i; j < iSize - 1; j++) { Bytes[j] = Bytes[j + 1]; } iSize--; } } for (int i = 0; i < iSize; i++) { deleteString += Bytes[i]; } return deleteString; }

第九种方法

原理与 第一种方法 类似,本次采用 stringBuffer 类中的 append 方法进行操作,我认为效率应该高于第一种。

public String deleteCharString8(String sourceString, char chElemData) { StringBuffer stringBuffer = new StringBuffer(""); for (int i = 0; i < sourceString.length(); i++) { if (sourceString.charAt(i) != chElemData) { stringBuffer.append(sourceString.charAt(i)); } } return stringBuffer.toString(); }

第十种方法

采用 stringBuffer 类中的 replace and indexOf 方法(_ 故意凑方法),代码如下:

public String deleteCharString9(String sourceString, char chElemData) { String tmpString = ""; tmpString += chElemData; StringBuffer stringBuffer = new StringBuffer(sourceString); int iFlag = -1; do { iFlag = stringBuffer.indexOf(tmpString); if (iFlag != -1) { stringBuffer = stringBuffer.replace(iFlag, iFlag + 1, ""); } } while (iFlag != -1); return stringBuffer.toString(); }

第十一种方法

采用 stringBuffer 类中的 deleteCharAt 和 indexOf 直接删除

public String deleteCharString10(String sourceString, char chElemData) { String tmpString = ""; tmpString += chElemData; StringBuffer stringBuffer = new StringBuffer(sourceString); int iFlag = -1; do { iFlag = stringBuffer.indexOf(tmpString); if (iFlag != -1) { stringBuffer.deleteCharAt(iFlag); } } while (iFlag != -1); return stringBuffer.toString(); }

程序运行截图:

image

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