等高线标签演示

2023-10-03 13:44| 来源: 网络整理| 查看: 265

# 等高线标签演示

说明一些可以用等高线的标签做的更高级的东西。

另请参见轮廓演示示例open in new window。

import matplotlib import numpy as np import matplotlib.ticker as ticker import matplotlib.pyplot as plt

定义我们的外观

delta = 0.025 x = np.arange(-3.0, 3.0, delta) y = np.arange(-2.0, 2.0, delta) X, Y = np.meshgrid(x, y) Z1 = np.exp(-X**2 - Y**2) Z2 = np.exp(-(X - 1)**2 - (Y - 1)**2) Z = (Z1 - Z2) * 2

使用创造性的浮动类制作等高线的标签，遵循曼纽尔·梅茨的建议。

# Define a class that forces representation of float to look a certain way # This remove trailing zero so '1.0' becomes '1' class nf(float): def __repr__(self): str = '%.1f' % (self.__float__(),) if str[-1] == '0': return '%.0f' % self.__float__() else: return '%.1f' % self.__float__() # Basic contour plot fig, ax = plt.subplots() CS = ax.contour(X, Y, Z) # Recast levels to new class CS.levels = [nf(val) for val in CS.levels] # Label levels with specially formatted floats if plt.rcParams["text.usetex"]: fmt = r'%r \%%' else: fmt = '%r %%' ax.clabel(CS, CS.levels, inline=True, fmt=fmt, fontsize=10)

等高线标签演示示例

使用字典用任意字符串标记等高线

fig1, ax1 = plt.subplots() # Basic contour plot CS1 = ax1.contour(X, Y, Z) fmt = {} strs = ['first', 'second', 'third', 'fourth', 'fifth', 'sixth', 'seventh'] for l, s in zip(CS1.levels, strs): fmt[l] = s # Label every other level using strings ax1.clabel(CS1, CS1.levels[::2], inline=True, fmt=fmt, fontsize=10)

等高线标签演示示例2

使用Formatter来格式化

fig2, ax2 = plt.subplots() CS2 = ax2.contour(X, Y, 100**Z, locator=plt.LogLocator()) fmt = ticker.LogFormatterMathtext() fmt.create_dummy_axis() ax2.clabel(CS2, CS2.levels, fmt=fmt) ax2.set_title("$100^Z$") plt.show()

等高线标签演示示例3

# 参考

本例中显示了以下函数、方法和类的使用：

matplotlib.axes.Axes.contour matplotlib.pyplot.contour matplotlib.axes.Axes.clabel matplotlib.pyplot.clabel matplotlib.ticker.LogFormatterMathtext matplotlib.ticker.TickHelper.create_dummy_axis # 下载这个示例下载python源码: contour_image.pyopen in new window下载Jupyter notebook: contour_image.ipynbopen in new window

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等高线标签演示

等高线标签演示

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