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C语言字符串十进制IP地址与十六进制转换
提示：for循环太low了，代码用位运算
1、 输入：192.168.1.155 输出：0xc0a8019b
#include
#include
#include
unsigned int Covert(char *message)
{
char *p[4] = {0};
char *last;
p[0] = strtok_r(message, ".", &last);
p[1] = strtok_r(NULL, ".", &last);
p[3] = strtok_r(NULL, ".", &last);
return (atoi(p[0])8),(unsigned char)ip );
}
unsigned int change2(unsigned int ip, char *mm)
{
sprintf(mm, "%d.%d.%d.%d", (ip & 0xff000000)>>24, ip & 0xff0000)>>16, (ip & 0xff00)>>8,(ip & 0xff);
}
unsigned int change3(unsigned int ip, char *mm)
{
sprintf(mm, "%d.%d.%d.%d", (ip>>24) & 0xff, (ip>>16) & 0xff, (ip>>8) & 0xff, ip &0xff);
}
int main()
{
char message[32] = {0};
change1(0xc0a8019b, message);
printf("10进制的ip地址是:%s\n", message);
return 0;
}
注意：位运算很强大，建议大家多用位运算解决问题。
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