c/c++生成md5,并将md5结果转换char *

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c/c++生成md5,并将md5结果转换char *

2024-06-30 18:44| 来源: 网络整理| 查看: 265

项目开发中需要c/c++版本的md5算法,在网上找了一个代码例子,并做了测试,代码如下:

md5代码:

头文件

#ifndef MD5_H #define MD5_H typedef struct { unsigned int count[2]; unsigned int state[4]; unsigned char buffer[64]; }MD5_CTX; #define F(x,y,z) ((x & y) | (~x & z)) #define G(x,y,z) ((x & z) | (y & ~z)) #define H(x,y,z) (x^y^z) #define I(x,y,z) (y ^ (x | ~z)) #define ROTATE_LEFT(x,n) ((x > (32-n))) #define FF(a,b,c,d,x,s,ac)\ {\ a += F(b, c, d) + x + ac;\ a = ROTATE_LEFT(a, s);\ a += b;\ } #define GG(a,b,c,d,x,s,ac)\ {\ a += G(b, c, d) + x + ac;\ a = ROTATE_LEFT(a, s);\ a += b;\ } #define HH(a,b,c,d,x,s,ac)\ {\ a += H(b, c, d) + x + ac;\ a = ROTATE_LEFT(a, s);\ a += b; \ } #define II(a,b,c,d,x,s,ac)\ {\ a += I(b, c, d) + x + ac;\ a = ROTATE_LEFT(a, s);\ a += b;\ } void MD5Init(MD5_CTX *context); void MD5Update(MD5_CTX *context, unsigned char *input, unsigned int inputlen); void MD5Final(MD5_CTX *context, unsigned char digest[16]); void MD5Transform(unsigned int state[4], unsigned char block[64]); void MD5Encode(unsigned char *output, unsigned int *input, unsigned int len); void MD5Decode(unsigned int *output, unsigned char *input, unsigned int len); #endif

.cpp文件

#include #include "md5.h" unsigned char PADDING[] = { 0x80, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 }; void MD5Init(MD5_CTX *context) { context->count[0] = 0; context->count[1] = 0; context->state[0] = 0x67452301; context->state[1] = 0xEFCDAB89; context->state[2] = 0x98BADCFE; context->state[3] = 0x10325476; } void MD5Update(MD5_CTX *context, unsigned char *input, unsigned int inputlen) { unsigned int i = 0, index = 0, partlen = 0; index = (context->count[0] >> 3) & 0x3F; partlen = 64 - index; context->count[0] += inputlen count[0] < (inputlen count[1]++; context->count[1] += inputlen >> 29; if (inputlen >= partlen) { memcpy(&context->buffer[index], input, partlen); MD5Transform(context->state, context->buffer); for (i = partlen; i + 64 state, &input[i]); index = 0; } else { i = 0; } memcpy(&context->buffer[index], &input[i], inputlen - i); } void MD5Final(MD5_CTX *context, unsigned char digest[16]) { unsigned int index = 0, padlen = 0; unsigned char bits[8]; index = (context->count[0] >> 3) & 0x3F; padlen = (index < 56) ? (56 - index) : (120 - index); MD5Encode(bits, context->count, 8); MD5Update(context, PADDING, padlen); MD5Update(context, bits, 8); MD5Encode(digest, context->state, 16); } void MD5Encode(unsigned char *output, unsigned int *input, unsigned int len) { unsigned int i = 0, j = 0; while (j < len) { output[j] = input[i] & 0xFF; output[j + 1] = (input[i] >> 8) & 0xFF; output[j + 2] = (input[i] >> 16) & 0xFF; output[j + 3] = (input[i] >> 24) & 0xFF; i++; j += 4; } } void MD5Decode(unsigned int *output, unsigned char *input, unsigned int len) { unsigned int i = 0, j = 0; while (j < len) { output[i] = (input[j]) | (input[j + 1]


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