ggks: 大佬那么接下来如何获取具体是哪一个元素呢

做而论道_CS: DATAS SEGMENT MSG1 DB 'Enter 4 hexadecimal number: $' MSG2 DB 10, 13, 'The binary number is: $' DATAS ENDS CODES SEGMENT ASSUME CS:CODES, DS:DATAS MAIN: MOV AX, DATAS MOV DS, AX LEA DX, MSG1 MOV AH, 9 INT 21H MOV BX, 0 MOV CX, 4 ;输入字符个数 IN_N: MOV AH, 7 ;输入一个 INT 21H CMP AL, 13 JZ IN_E MOV DL, AL MOV DH, AL CMP DH, '0' JB IN_N CMP DH, 'F' JA IN_N CMP DH, '9' JA IN_2 SUB DH, '0' JMP IN_X IN_2: CMP DH, 'A' JB IN_N SUB DH, 37H IN_X: SHL BX, 1 SHL BX, 1 SHL BX, 1 SHL BX, 1 ADD BL, DH MOV AH, 2 INT 21H LOOP IN_N IN_E: LEA DX, MSG2 MOV AH, 9 INT 21H MOV CX, 16 MOV AH, 2 MOV DH, 4 OUT_B: MOV DL, '0' ADD BX, BX ADC DL, 0 INT 21H DEC DH JNZ OUT_C MOV DH, 4 MOV DL, ' ' INT 21H OUT_C: LOOP OUT_B MOV AH, 4CH INT 21H CODES ENDS END MAIN

java持续实践: [code=plain] yum install -y unzip zip [/code]

羌恙: 请问最后一部分的最后一行代码是没有写完吗？

2301_82301511: int max(int a, int b, int c, int d) { int m = a; if (b > m) m = b; if (c > m) m = c; if (d > m) m = d; return m; } 1 2 3 4 5 6 7 8 9